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avcodec/alac: Fix multiple integer overflows in lpc_prediction()

Fixes: signed integer overflow: 2088795537 + 2147254401 cannot be represented in type 'int'
Fixes: signed integer overflow: -1500363496 + -1295351808 cannot be represented in type 'int'
Fixes: signed integer overflow: -79560 * 32640 cannot be represented in type 'int'
Fixes: signed integer overflow: 2088910005 + 2088796058 cannot be represented in type 'int'
Fixes: signed integer overflow: -117258064 - 2088725225 cannot be represented in type 'int'
Fixes: signed integer overflow: 2088725225 - -117258064 cannot be represented in type 'int'
Fixes: 15739/clusterfuzz-testcase-minimized-ffmpeg_AV_CODEC_ID_ALAC_fuzzer-5630664122040320

Found-by: continuous fuzzing process https://github.com/google/oss-fuzz/tree/master/projects/ffmpeg
Signed-off-by: Michael Niedermayer <michael@niedermayer.cc>

Michael Niedermayer authored on 2019/08/09 02:48:19
Showing 1 changed files
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@@ -171,12 +171,12 @@ static inline int sign_only(int v)
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     return v ? FFSIGN(v) : 0;
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 }
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-static void lpc_prediction(int32_t *error_buffer, int32_t *buffer_out,
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+static void lpc_prediction(int32_t *error_buffer, uint32_t *buffer_out,
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                            int nb_samples, int bps, int16_t *lpc_coefs,
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                            int lpc_order, int lpc_quant)
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 {
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     int i;
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-    int32_t *pred = buffer_out;
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+    uint32_t *pred = buffer_out;
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     /* first sample always copies */
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     *buffer_out = *error_buffer;
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@@ -208,7 +208,7 @@ static void lpc_prediction(int32_t *error_buffer, int32_t *buffer_out,
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     for (; i < nb_samples; i++) {
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         int j;
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         int val = 0;
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-        int error_val = error_buffer[i];
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+        unsigned error_val = error_buffer[i];
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         int error_sign;
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         int d = *pred++;
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@@ -222,7 +222,7 @@ static void lpc_prediction(int32_t *error_buffer, int32_t *buffer_out,
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         /* adapt LPC coefficients */
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         error_sign = sign_only(error_val);
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         if (error_sign) {
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-            for (j = 0; j < lpc_order && error_val * error_sign > 0; j++) {
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+            for (j = 0; j < lpc_order && (int)error_val * error_sign > 0; j++) {
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                 int sign;
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                 val  = d - pred[j];
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                 sign = sign_only(val) * error_sign;